\(\int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx\) [2435]

Optimal result

Integrand size = 18, antiderivative size = 33 \[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} (1-x)}{\sqrt {-2+4 x-3 x^2}}\right )}{\sqrt {2}} \]

[Out]

-1/2*arctan((1-x)*2^(1/2)/(-3*x^2+4*x-2)^(1/2))*2^(1/2)

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {738, 210} \[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=-\frac {\arctan \left (\frac {\sqrt {2} (1-x)}{\sqrt {-3 x^2+4 x-2}}\right )}{\sqrt {2}} \]

[In]

Int[1/(x*Sqrt[-2 + 4*x - 3*x^2]),x]

[Out]

-(ArcTan[(Sqrt[2]*(1 - x))/Sqrt[-2 + 4*x - 3*x^2]]/Sqrt[2])

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 738

Int[1/(((d_.) + (e_.)*(x_))*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Symbol] :> Dist[-2, Subst[Int[1/(4*c*d
^2 - 4*b*d*e + 4*a*e^2 - x^2), x], x, (2*a*e - b*d - (2*c*d - b*e)*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a,
b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[2*c*d - b*e, 0]

Rubi steps \begin{align*} \text {integral}& = -\left (2 \text {Subst}\left (\int \frac {1}{-8-x^2} \, dx,x,\frac {-4+4 x}{\sqrt {-2+4 x-3 x^2}}\right )\right ) \\ & = -\frac {\tan ^{-1}\left (\frac {\sqrt {2} (1-x)}{\sqrt {-2+4 x-3 x^2}}\right )}{\sqrt {2}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.07 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82 \[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=\frac {\arctan \left (\frac {-1+x}{\sqrt {-1+2 x-\frac {3 x^2}{2}}}\right )}{\sqrt {2}} \]

[In]

Integrate[1/(x*Sqrt[-2 + 4*x - 3*x^2]),x]

[Out]

ArcTan[(-1 + x)/Sqrt[-1 + 2*x - (3*x^2)/2]]/Sqrt[2]

Maple [A] (verified)

Time = 0.24 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.88

method	result	size
default	\(\frac {\sqrt {2}\, \arctan \left (\frac {\left (-4+4 x \right ) \sqrt {2}}{4 \sqrt {-3 x^{2}+4 x -2}}\right )}{2}\)	\(29\)
trager	\(\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) \ln \left (\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) \sqrt {-3 x^{2}+4 x -2}+2 x -2}{x}\right )}{2}\)	\(38\)

[In]

int(1/x/(-3*x^2+4*x-2)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/2*2^(1/2)*arctan(1/4*(-4+4*x)*2^(1/2)/(-3*x^2+4*x-2)^(1/2))

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 64 vs. \(2 (26) = 52\).

Time = 0.36 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.94 \[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=\frac {1}{4} \, \sqrt {-2} \log \left (\frac {\sqrt {-2} \sqrt {-3 \, x^{2} + 4 \, x - 2} + 2 \, x - 2}{x}\right ) - \frac {1}{4} \, \sqrt {-2} \log \left (-\frac {\sqrt {-2} \sqrt {-3 \, x^{2} + 4 \, x - 2} - 2 \, x + 2}{x}\right ) \]

[In]

integrate(1/x/(-3*x^2+4*x-2)^(1/2),x, algorithm="fricas")

[Out]

1/4*sqrt(-2)*log((sqrt(-2)*sqrt(-3*x^2 + 4*x - 2) + 2*x - 2)/x) - 1/4*sqrt(-2)*log(-(sqrt(-2)*sqrt(-3*x^2 + 4*
x - 2) - 2*x + 2)/x)

Sympy [F]

\[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=\int \frac {1}{x \sqrt {- 3 x^{2} + 4 x - 2}}\, dx \]

[In]

integrate(1/x/(-3*x**2+4*x-2)**(1/2),x)

[Out]

Integral(1/(x*sqrt(-3*x**2 + 4*x - 2)), x)

Maxima [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.28 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.76 \[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=\frac {1}{2} i \, \sqrt {2} \operatorname {arsinh}\left (\frac {\sqrt {2} x}{{\left | x \right |}} - \frac {\sqrt {2}}{{\left | x \right |}}\right ) \]

[In]

integrate(1/x/(-3*x^2+4*x-2)^(1/2),x, algorithm="maxima")

[Out]

1/2*I*sqrt(2)*arcsinh(sqrt(2)*x/abs(x) - sqrt(2)/abs(x))

Giac [F]

\[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=\int { \frac {1}{\sqrt {-3 \, x^{2} + 4 \, x - 2} x} \,d x } \]

[In]

integrate(1/x/(-3*x^2+4*x-2)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(-3*x^2 + 4*x - 2)*x), x)

Mupad [B] (verification not implemented)

Time = 10.15 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.03 \[ \int \frac {1}{x \sqrt {-2+4 x-3 x^2}} \, dx=\frac {\sqrt {2}\,\ln \left (\frac {2\,x-2+\sqrt {2}\,\sqrt {-3\,x^2+4\,x-2}\,1{}\mathrm {i}}{x}\right )\,1{}\mathrm {i}}{2} \]

[In]

int(1/(x*(4*x - 3*x^2 - 2)^(1/2)),x)

[Out]

(2^(1/2)*log((2*x + 2^(1/2)*(4*x - 3*x^2 - 2)^(1/2)*1i - 2)/x)*1i)/2